0=10x^2-17x+6

Solution for 0=10x^2-17x+6 equation:

0=10x^2-17x+6

We move all terms to the left:

0-(10x^2-17x+6)=0

We add all the numbers together, and all the variables

-(10x^2-17x+6)=0

We get rid of parentheses

-10x^2+17x-6=0

a = -10; b = 17; c = -6;
Δ = b2-4ac
Δ = 172-4·(-10)·(-6)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*-10}=\frac{-24}{-20}
=1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*-10}=\frac{-10}{-20}
=1/2
$